Base | Representation |
---|---|
bin | 111111001001101001… |
… | …1011110001110001011 |
3 | 110222001021012010222010 |
4 | 1332103103132032023 |
5 | 4210220011411301 |
6 | 142144551231003 |
7 | 12540450245142 |
oct | 1762323361613 |
9 | 428037163863 |
10 | 135615341451 |
11 | 52572363297 |
12 | 22349378463 |
13 | ca33370b95 |
14 | 67c7188759 |
15 | 37dad185d6 |
hex | 1f934de38b |
135615341451 has 4 divisors (see below), whose sum is σ = 180820455272. Its totient is φ = 90410227632.
The previous prime is 135615341441. The next prime is 135615341461. The reversal of 135615341451 is 154143516531.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (135615341441) and next prime (135615341461).
It is not a de Polignac number, because 135615341451 - 230 = 134541599627 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135615341441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22602556906 + ... + 22602556911.
It is an arithmetic number, because the mean of its divisors is an integer number (45205113818).
Almost surely, 2135615341451 is an apocalyptic number.
135615341451 is a deficient number, since it is larger than the sum of its proper divisors (45205113821).
135615341451 is an equidigital number, since it uses as much as digits as its factorization.
135615341451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45205113820.
The product of its digits is 108000, while the sum is 39.
Adding to 135615341451 its reverse (154143516531), we get a palindrome (289758857982).
The spelling of 135615341451 in words is "one hundred thirty-five billion, six hundred fifteen million, three hundred forty-one thousand, four hundred fifty-one".
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