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135628536533041 = 314375114081711
BaseRepresentation
bin11110110101101001111010…
…101111011101000000110001
3122210012221221220111112210101
4132311221322233131000301
5120234114220323024131
61200242520045432401
740365560366641156
oct3665517257350061
9583187856445711
10135628536533041
113a240815053992
121326587656b701
135a8a9403cb256
14256c655b2022d
1510a3022031c61
hex7b5a7abdd031

135628536533041 has 4 divisors (see below), whose sum is σ = 140003650614784. Its totient is φ = 131253422451300.

The previous prime is 135628536533033. The next prime is 135628536533047. The reversal of 135628536533041 is 140335635826531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135628536533041 - 23 = 135628536533033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135628536533047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187557040825 + ... + 2187557040886.

It is an arithmetic number, because the mean of its divisors is an integer number (35000912653696).

Almost surely, 2135628536533041 is an apocalyptic number.

It is an amenable number.

135628536533041 is a deficient number, since it is larger than the sum of its proper divisors (4375114081743).

135628536533041 is an equidigital number, since it uses as much as digits as its factorization.

135628536533041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4375114081742.

The product of its (nonzero) digits is 23328000, while the sum is 55.

The spelling of 135628536533041 in words is "one hundred thirty-five trillion, six hundred twenty-eight billion, five hundred thirty-six million, five hundred thirty-three thousand, forty-one".

Divisors: 1 31 4375114081711 135628536533041