Base | Representation |
---|---|
bin | 11110110110101000001001… |
… | …111100011110000011110011 |
3 | 122210110100110012102010000221 |
4 | 132312220021330132003303 |
5 | 120241213101040042111 |
6 | 1200333331153353511 |
7 | 40403444415416104 |
oct | 3666501174360363 |
9 | 583410405363027 |
10 | 135695363596531 |
11 | 3a2670981a7882 |
12 | 13276806868897 |
13 | 5a9403039157b |
14 | 25719951943ab |
15 | 10a4b33cdd371 |
hex | 7b6a09f1e0f3 |
135695363596531 has 4 divisors (see below), whose sum is σ = 135916726343632. Its totient is φ = 135474000849432.
The previous prime is 135695363596511. The next prime is 135695363596607.
135695363596531 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135695363596531 - 213 = 135695363588339 is a prime.
It is a super-2 number, since 2×1356953635965312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135695363596501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110681372631 + ... + 110681373856.
It is an arithmetic number, because the mean of its divisors is an integer number (33979181585908).
Almost surely, 2135695363596531 is an apocalyptic number.
135695363596531 is a deficient number, since it is larger than the sum of its proper divisors (221362747101).
135695363596531 is an equidigital number, since it uses as much as digits as its factorization.
135695363596531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 221362747100.
The product of its digits is 885735000, while the sum is 70.
The spelling of 135695363596531 in words is "one hundred thirty-five trillion, six hundred ninety-five billion, three hundred sixty-three million, five hundred ninety-six thousand, five hundred thirty-one".
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