135783511403 has 4 divisors (see below), whose sum is σ = 135792950640. Its totient is φ = 135774072168.

The previous prime is 135783511399. The next prime is 135783511411. The reversal of 135783511403 is 304115387531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135783511403 - 2² = 135783511399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135783511453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4698008 + ... + 4726821.

It is an arithmetic number, because the mean of its divisors is an integer number (33948237660).

Almost surely, 2^135783511403 is an apocalyptic number.

135783511403 is a deficient number, since it is larger than the sum of its proper divisors (9439237).

135783511403 is an equidigital number, since it uses as much as digits as its factorization.

135783511403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9439236.

The product of its (nonzero) digits is 151200, while the sum is 41.

Adding to 135783511403 its reverse (304115387531), we get a palindrome (439898898934).

The spelling of 135783511403 in words is "one hundred thirty-five billion, seven hundred eighty-three million, five hundred eleven thousand, four hundred three".