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1360143113 = 7194306159
BaseRepresentation
bin101000100010010…
…0010001100001001
310111210100102120212
41101010202030021
510241144034423
6342544330505
745464011550
oct12104421411
93453312525
101360143113
1163884671a
1231b613a35
13188a35114
14cc8d8d97
157e620578
hex51122309

1360143113 has 4 divisors (see below), whose sum is σ = 1554449280. Its totient is φ = 1165836948.

The previous prime is 1360143097. The next prime is 1360143137. The reversal of 1360143113 is 3113410631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1360143113 - 24 = 1360143097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1360143173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97153073 + ... + 97153086.

It is an arithmetic number, because the mean of its divisors is an integer number (388612320).

Almost surely, 21360143113 is an apocalyptic number.

It is an amenable number.

1360143113 is a deficient number, since it is larger than the sum of its proper divisors (194306167).

1360143113 is an equidigital number, since it uses as much as digits as its factorization.

1360143113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 194306166.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 1360143113 is about 36880.1181261666. The cubic root of 1360143113 is about 1107.9705125913.

Adding to 1360143113 its reverse (3113410631), we get a palindrome (4473553744).

The spelling of 1360143113 in words is "one billion, three hundred sixty million, one hundred forty-three thousand, one hundred thirteen".

Divisors: 1 7 194306159 1360143113