1360314113 has 4 divisors (see below), whose sum is σ = 1393492548. Its totient is φ = 1327135680.

The previous prime is 1360314083. The next prime is 1360314119. The reversal of 1360314113 is 3114130631.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3114130631 = 1399 ⋅2225969.

It can be written as a sum of positive squares in 2 ways, for example, as 785849089 + 574465024 = 28033^2 + 23968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1360314113 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1360314119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16589156 + ... + 16589237.

It is an arithmetic number, because the mean of its divisors is an integer number (348373137).

Almost surely, 2^1360314113 is an apocalyptic number.

It is an amenable number.

1360314113 is a deficient number, since it is larger than the sum of its proper divisors (33178435).

1360314113 is an equidigital number, since it uses as much as digits as its factorization.

1360314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33178434.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 1360314113 is about 36882.4363755975. The cubic root of 1360314113 is about 1108.0169427590.

Adding to 1360314113 its reverse (3114130631), we get a palindrome (4474444744).

The spelling of 1360314113 in words is "one billion, three hundred sixty million, three hundred fourteen thousand, one hundred thirteen".