Base | Representation |
---|---|
bin | 11001010101101110… |
… | …10010110011001001 |
3 | 1022010002101211101221 |
4 | 30222313102303021 |
5 | 210330113234011 |
6 | 10125525442041 |
7 | 661056300565 |
oct | 145267226311 |
9 | 38102354357 |
10 | 13604039881 |
11 | 5851142573 |
12 | 2777b70321 |
13 | 138a583353 |
14 | 930a846a5 |
15 | 5494bb971 |
hex | 32add2cc9 |
13604039881 has 6 divisors (see below), whose sum is σ = 14357726682. Its totient is φ = 12888037440.
The previous prime is 13604039837. The next prime is 13604039887. The reversal of 13604039881 is 18893040631.
It can be written as a sum of positive squares in only one way, i.e., 13384407481 + 219632400 = 115691^2 + 14820^2 .
It is not a de Polignac number, because 13604039881 - 215 = 13604007113 is a prime.
It is a super-2 number, since 2×136040398812 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13604039887) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 18841800 + ... + 18842521.
It is an arithmetic number, because the mean of its divisors is an integer number (2392954447).
Almost surely, 213604039881 is an apocalyptic number.
It is an amenable number.
13604039881 is a deficient number, since it is larger than the sum of its proper divisors (753686801).
13604039881 is an equidigital number, since it uses as much as digits as its factorization.
13604039881 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37684359 (or 37684340 counting only the distinct ones).
The product of its (nonzero) digits is 124416, while the sum is 43.
The spelling of 13604039881 in words is "thirteen billion, six hundred four million, thirty-nine thousand, eight hundred eighty-one".
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