13604043544331 has 4 divisors (see below), whose sum is σ = 13604380794192. Its totient is φ = 13603706294472.

The previous prime is 13604043544321. The next prime is 13604043544337. The reversal of 13604043544331 is 13344534040631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13604043544331 is a prime.

It is a super-2 number, since 2×13604043544331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13604043544337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168564416 + ... + 168645101.

It is an arithmetic number, because the mean of its divisors is an integer number (3401095198548).

Almost surely, 2^{13604043544331} is an apocalyptic number.

13604043544331 is a deficient number, since it is larger than the sum of its proper divisors (337249861).

13604043544331 is an equidigital number, since it uses as much as digits as its factorization.

13604043544331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 337249860.

The product of its (nonzero) digits is 622080, while the sum is 41.

Adding to 13604043544331 its reverse (13344534040631), we get a palindrome (26948577584962).

The spelling of 13604043544331 in words is "thirteen trillion, six hundred four billion, forty-three million, five hundred forty-four thousand, three hundred thirty-one".