1360404354577 has 4 divisors (see below), whose sum is σ = 1360573168240. Its totient is φ = 1360235540916.

The previous prime is 1360404354563. The next prime is 1360404354599. The reversal of 1360404354577 is 7754534040631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1360404354577 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1360404354577.

It is not an unprimeable number, because it can be changed into a prime (1360404354277) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84394743 + ... + 84410860.

It is an arithmetic number, because the mean of its divisors is an integer number (340143292060).

Almost surely, 2^{1360404354577} is an apocalyptic number.

It is an amenable number.

1360404354577 is a deficient number, since it is larger than the sum of its proper divisors (168813663).

1360404354577 is an equidigital number, since it uses as much as digits as its factorization.

1360404354577 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 168813662.

The product of its (nonzero) digits is 4233600, while the sum is 49.

The spelling of 1360404354577 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred fifty-four thousand, five hundred seventy-seven".