136040471403 has 4 divisors (see below), whose sum is σ = 181387295208. Its totient is φ = 90693647600.

The previous prime is 136040471383. The next prime is 136040471423. The reversal of 136040471403 is 304174040631.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304174040631 = 3 ⋅101391346877.

It is an interprime number because it is at equal distance from previous prime (136040471383) and next prime (136040471423).

It is a cyclic number.

It is not a de Polignac number, because 136040471403 - 2¹³ = 136040463211 is a prime.

It is not an unprimeable number, because it can be changed into a prime (136040471423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22673411898 + ... + 22673411903.

It is an arithmetic number, because the mean of its divisors is an integer number (45346823802).

Almost surely, 2^136040471403 is an apocalyptic number.

136040471403 is a deficient number, since it is larger than the sum of its proper divisors (45346823805).

136040471403 is an equidigital number, since it uses as much as digits as its factorization.

136040471403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45346823804.

The product of its (nonzero) digits is 24192, while the sum is 33.

The spelling of 136040471403 in words is "one hundred thirty-six billion, forty million, four hundred seventy-one thousand, four hundred three".