Base | Representation |
---|---|
bin | 11110111011101001101011… |
… | …111101111101111010100011 |
3 | 122211200100120201000222220001 |
4 | 132323221223331331322203 |
5 | 120312342130004240003 |
6 | 1201200105202400431 |
7 | 40440416011465333 |
oct | 3673515375757243 |
9 | 584610521028801 |
10 | 136040605540003 |
11 | 3a38a55128a8aa |
12 | 133116b7660117 |
13 | 5aba760282918 |
14 | 2584586b450c3 |
15 | 10adadd27c61d |
hex | 7bba6bf7dea3 |
136040605540003 has 8 divisors (see below), whose sum is σ = 138176687447568. Its totient is φ = 133916357881824.
The previous prime is 136040605539869. The next prime is 136040605540019. The reversal of 136040605540003 is 300045506040631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136040605540003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (136040605541003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2958539176 + ... + 2958585157.
It is an arithmetic number, because the mean of its divisors is an integer number (17272085930946).
Almost surely, 2136040605540003 is an apocalyptic number.
136040605540003 is a deficient number, since it is larger than the sum of its proper divisors (2136081907565).
136040605540003 is an equidigital number, since it uses as much as digits as its factorization.
136040605540003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5917124693.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 136040605540003 in words is "one hundred thirty-six trillion, forty billion, six hundred five million, five hundred forty thousand, three".
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