Base | Representation |
---|---|
bin | 111111010110100111… |
… | …0000111101111000001 |
3 | 111000011120100112000020 |
4 | 1332231032013233001 |
5 | 4212112314134431 |
6 | 142300042444053 |
7 | 12554310106452 |
oct | 1765516075701 |
9 | 430146315006 |
10 | 136050146241 |
11 | 52775840599 |
12 | 2244ab03629 |
13 | caa247a419 |
14 | 6828c0d129 |
15 | 38140a4696 |
hex | 1fad387bc1 |
136050146241 has 4 divisors (see below), whose sum is σ = 181400194992. Its totient is φ = 90700097492.
The previous prime is 136050146213. The next prime is 136050146249. The reversal of 136050146241 is 142641050631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 136050146241 - 29 = 136050145729 is a prime.
It is not an unprimeable number, because it can be changed into a prime (136050146249) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22675024371 + ... + 22675024376.
It is an arithmetic number, because the mean of its divisors is an integer number (45350048748).
Almost surely, 2136050146241 is an apocalyptic number.
It is an amenable number.
136050146241 is a deficient number, since it is larger than the sum of its proper divisors (45350048751).
136050146241 is an equidigital number, since it uses as much as digits as its factorization.
136050146241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45350048750.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 136050146241 its reverse (142641050631), we get a palindrome (278691196872).
The spelling of 136050146241 in words is "one hundred thirty-six billion, fifty million, one hundred forty-six thousand, two hundred forty-one".
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