Base | Representation |
---|---|
bin | 10000001110011… |
… | …10000010111011 |
3 | 100111010010012000 |
4 | 20013032002323 |
5 | 234321012032 |
6 | 21301152043 |
7 | 3241626636 |
oct | 1007160273 |
9 | 314103160 |
10 | 136110267 |
11 | 6a915727 |
12 | 396bb623 |
13 | 22277a27 |
14 | 14110c1d |
15 | be38e7c |
hex | 81ce0bb |
136110267 has 8 divisors (see below), whose sum is σ = 201644880. Its totient is φ = 90740160.
The previous prime is 136110257. The next prime is 136110287. The reversal of 136110267 is 762011631.
It is not a de Polignac number, because 136110267 - 26 = 136110203 is a prime.
It is a super-2 number, since 2×1361102672 = 37052009565622578, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 5041121 = 136110267 / (1 + 3 + 6 + 1 + 1 + 0 + 2 + 6 + 7).
It is a self number, because there is not a number n which added to its sum of digits gives 136110267.
It is not an unprimeable number, because it can be changed into a prime (136110217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2520534 + ... + 2520587.
It is an arithmetic number, because the mean of its divisors is an integer number (25205610).
Almost surely, 2136110267 is an apocalyptic number.
136110267 is a deficient number, since it is larger than the sum of its proper divisors (65534613).
136110267 is an equidigital number, since it uses as much as digits as its factorization.
136110267 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5041130 (or 5041124 counting only the distinct ones).
The product of its (nonzero) digits is 1512, while the sum is 27.
The square root of 136110267 is about 11666.6304904201. The cubic root of 136110267 is about 514.3952646585.
Adding to 136110267 its reverse (762011631), we get a palindrome (898121898).
It can be divided in two parts, 1361 and 10267, that added together give a triangular number (11628 = T152).
The spelling of 136110267 in words is "one hundred thirty-six million, one hundred ten thousand, two hundred sixty-seven".
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