Base | Representation |
---|---|
bin | 10011110011101110001… |
… | …011000110110100010011 |
3 | 11211010111202101202210020 |
4 | 103303232023012310103 |
5 | 134300222110220301 |
6 | 2521155035034523 |
7 | 200225641210161 |
oct | 23635613066423 |
9 | 4733452352706 |
10 | 1361205554451 |
11 | 48531405a146 |
12 | 19b988b9ba43 |
13 | 9b490542052 |
14 | 49c501b6231 |
15 | 2561c40e436 |
hex | 13cee2c6d13 |
1361205554451 has 4 divisors (see below), whose sum is σ = 1814940739272. Its totient is φ = 907470369632.
The previous prime is 1361205554413. The next prime is 1361205554453. The reversal of 1361205554451 is 1544555021631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1361205554451 - 211 = 1361205552403 is a prime.
It is a super-2 number, since 2×13612055544512 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1361205554453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226867592406 + ... + 226867592411.
It is an arithmetic number, because the mean of its divisors is an integer number (453735184818).
Almost surely, 21361205554451 is an apocalyptic number.
1361205554451 is a deficient number, since it is larger than the sum of its proper divisors (453735184821).
1361205554451 is an equidigital number, since it uses as much as digits as its factorization.
1361205554451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 453735184820.
The product of its (nonzero) digits is 360000, while the sum is 42.
The spelling of 1361205554451 in words is "one trillion, three hundred sixty-one billion, two hundred five million, five hundred fifty-four thousand, four hundred fifty-one".
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