1361211443331 has 8 divisors (see below), whose sum is σ = 1814954137344. Its totient is φ = 907471522440.

The previous prime is 1361211443327. The next prime is 1361211443363. The reversal of 1361211443331 is 1333441121631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1361211443331 - 2² = 1361211443327 is a prime.

It is a super-2 number, since 2×1361211443331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1361211443292 and 1361211443301.

It is not an unprimeable number, because it can be changed into a prime (1361211443381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1159170 + ... + 2016456.

It is an arithmetic number, because the mean of its divisors is an integer number (226869267168).

Almost surely, 2^{1361211443331} is an apocalyptic number.

1361211443331 is a deficient number, since it is larger than the sum of its proper divisors (453742694013).

1361211443331 is an equidigital number, since it uses as much as digits as its factorization.

1361211443331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1386561.

The product of its digits is 15552, while the sum is 33.

Adding to 1361211443331 its reverse (1333441121631), we get a palindrome (2694652564962).

The spelling of 1361211443331 in words is "one trillion, three hundred sixty-one billion, two hundred eleven million, four hundred forty-three thousand, three hundred thirty-one".