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1361250025003 = 11902913705837
BaseRepresentation
bin10011110011110000110…
…100101111111000101011
311211010121212002002220201
4103303300310233320223
5134300320001300003
62521203304133031
7200230021205011
oct23636064577053
94733555062821
101361250025003
11485337173570
1219b99ba67177
139b49981269b
1449c560708b1
1525621295b1d
hex13cf0d2fe2b

1361250025003 has 8 divisors (see below), whose sum is σ = 1485164605680. Its totient is φ = 1237362874080.

The previous prime is 1361250024991. The next prime is 1361250025063. The reversal of 1361250025003 is 3005200521631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1361250025003 - 25 = 1361250024971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1361250025063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6753600 + ... + 6952237.

It is an arithmetic number, because the mean of its divisors is an integer number (185645575710).

Almost surely, 21361250025003 is an apocalyptic number.

1361250025003 is a deficient number, since it is larger than the sum of its proper divisors (123914580677).

1361250025003 is a wasteful number, since it uses less digits than its factorization.

1361250025003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13714877.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 1361250025003 its reverse (3005200521631), we get a palindrome (4366450546634).

The spelling of 1361250025003 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, twenty-five thousand, three".

Divisors: 1 11 9029 99319 13705837 150764207 123750002273 1361250025003