Search a number
-
+
136134035 = 5211129037
BaseRepresentation
bin10000001110100…
…11110110010011
3100111011022210022
420013103312103
5234322242120
621301454055
73242056142
oct1007236623
9314138708
10136134035
116a931574
123971132b
13222857ab
1414119759
15be41025
hex81d3d93

136134035 has 8 divisors (see below), whose sum is σ = 164136336. Its totient is φ = 108390240.

The previous prime is 136134007. The next prime is 136134041. The reversal of 136134035 is 530431631.

136134035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 136134035 - 28 = 136133779 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136133995 and 136134013.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63464 + ... + 65573.

It is an arithmetic number, because the mean of its divisors is an integer number (20517042).

Almost surely, 2136134035 is an apocalyptic number.

136134035 is a deficient number, since it is larger than the sum of its proper divisors (28002301).

136134035 is a wasteful number, since it uses less digits than its factorization.

136134035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129253.

The product of its (nonzero) digits is 3240, while the sum is 26.

The square root of 136134035 is about 11667.6490776848. The cubic root of 136134035 is about 514.4252046852.

Adding to 136134035 its reverse (530431631), we get a palindrome (666565666).

The spelling of 136134035 in words is "one hundred thirty-six million, one hundred thirty-four thousand, thirty-five".

Divisors: 1 5 211 1055 129037 645185 27226807 136134035