Base | Representation |
---|---|
bin | 11110111101000111011001… |
… | …111110000110000101011011 |
3 | 122212000222022202201020001221 |
4 | 132331013121332012011123 |
5 | 120321014222220040120 |
6 | 1201314230423552511 |
7 | 40450610503453546 |
oct | 3675073176060533 |
9 | 585028282636057 |
10 | 136141235315035 |
11 | 3a4191a0160235 |
12 | 133291002bb737 |
13 | 5ac70a93b46c2 |
14 | 25893b169d85d |
15 | 10b152c9170aa |
hex | 7bd1d9f8615b |
136141235315035 has 4 divisors (see below), whose sum is σ = 163369482378048. Its totient is φ = 108912988252024.
The previous prime is 136141235314927. The next prime is 136141235315089. The reversal of 136141235315035 is 530513532141631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136141235315035 - 227 = 136141101097307 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 136141235314982 and 136141235315000.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13614123531499 + ... + 13614123531508.
It is an arithmetic number, because the mean of its divisors is an integer number (40842370594512).
Almost surely, 2136141235315035 is an apocalyptic number.
136141235315035 is a deficient number, since it is larger than the sum of its proper divisors (27228247063013).
136141235315035 is an equidigital number, since it uses as much as digits as its factorization.
136141235315035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27228247063012.
The product of its (nonzero) digits is 486000, while the sum is 43.
Adding to 136141235315035 its reverse (530513532141631), we get a palindrome (666654767456666).
The spelling of 136141235315035 in words is "one hundred thirty-six trillion, one hundred forty-one billion, two hundred thirty-five million, three hundred fifteen thousand, thirty-five".
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