Base | Representation |
---|---|
bin | 1100011000110011010000… |
… | …0000001011010110100011 |
3 | 1210020002011010002211222020 |
4 | 3012030310000023112203 |
5 | 3241123144210213342 |
6 | 44545012333512523 |
7 | 2604012410506521 |
oct | 306146400132643 |
9 | 53202133084866 |
10 | 13620213757347 |
11 | 438133365137a |
12 | 163b832042743 |
13 | 77a4c4383692 |
14 | 351316b15311 |
15 | 18945dde60ec |
hex | c633400b5a3 |
13620213757347 has 8 divisors (see below), whose sum is σ = 18468086450880. Its totient is φ = 8926241784360.
The previous prime is 13620213757313. The next prime is 13620213757357. The reversal of 13620213757347 is 74375731202631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13620213757347 - 211 = 13620213755299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13620213757347.
It is not an unprimeable number, because it can be changed into a prime (13620213757357) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38475179929 + ... + 38475180282.
It is an arithmetic number, because the mean of its divisors is an integer number (2308510806360).
Almost surely, 213620213757347 is an apocalyptic number.
13620213757347 is a deficient number, since it is larger than the sum of its proper divisors (4847872693533).
13620213757347 is an equidigital number, since it uses as much as digits as its factorization.
13620213757347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76950360273.
The product of its (nonzero) digits is 4445280, while the sum is 51.
Adding to 13620213757347 its reverse (74375731202631), we get a palindrome (87995944959978).
The spelling of 13620213757347 in words is "thirteen trillion, six hundred twenty billion, two hundred thirteen million, seven hundred fifty-seven thousand, three hundred forty-seven".
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