13620254023643 has 8 divisors (see below), whose sum is σ = 13633157563200. Its totient is φ = 13607353796488.

The previous prime is 13620254023619. The next prime is 13620254023721. The reversal of 13620254023643 is 34632045202631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13620254023643 is a prime.

It is a super-2 number, since 2×13620254023643² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13620254023643.

It is not an unprimeable number, because it can be changed into a prime (13620254029643) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7438628 + ... + 9087006.

It is an arithmetic number, because the mean of its divisors is an integer number (1704144695400).

Almost surely, 2^{13620254023643} is an apocalyptic number.

13620254023643 is a deficient number, since it is larger than the sum of its proper divisors (12903539557).

13620254023643 is a wasteful number, since it uses less digits than its factorization.

13620254023643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1656201.

The product of its (nonzero) digits is 622080, while the sum is 41.

The spelling of 13620254023643 in words is "thirteen trillion, six hundred twenty billion, two hundred fifty-four million, twenty-three thousand, six hundred forty-three".