Base | Representation |
---|---|
bin | 111111011100011100… |
… | …1101110001100100011 |
3 | 111000200020010021210122 |
4 | 1332320321232030203 |
5 | 4213013002002342 |
6 | 142331323150455 |
7 | 12562206646223 |
oct | 1767071561443 |
9 | 430606107718 |
10 | 136246125347 |
11 | 528664275a2 |
12 | 224a467542b |
13 | cb03c574a7 |
14 | 6846c66083 |
15 | 38263b74d2 |
hex | 1fb8e6e323 |
136246125347 has 4 divisors (see below), whose sum is σ = 136523612856. Its totient is φ = 135968637840.
The previous prime is 136246125287. The next prime is 136246125391. The reversal of 136246125347 is 743521642631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136246125347 - 26 = 136246125283 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 136246125298 and 136246125307.
It is not an unprimeable number, because it can be changed into a prime (136246125947) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138743018 + ... + 138743999.
It is an arithmetic number, because the mean of its divisors is an integer number (34130903214).
Almost surely, 2136246125347 is an apocalyptic number.
136246125347 is a deficient number, since it is larger than the sum of its proper divisors (277487509).
136246125347 is an equidigital number, since it uses as much as digits as its factorization.
136246125347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 277487508.
The product of its digits is 725760, while the sum is 44.
Adding to 136246125347 its reverse (743521642631), we get a palindrome (879767767978).
The spelling of 136246125347 in words is "one hundred thirty-six billion, two hundred forty-six million, one hundred twenty-five thousand, three hundred forty-seven".
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