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136254041243 = 3128571538429
BaseRepresentation
bin111111011100101011…
…1111010110010011011
3111000200210000110100222
41332321113322302123
54213022013304433
6142332204550255
712562334145515
oct1767127726233
9430623013328
10136254041243
115286a943961
12224a725238b
13cb05799558
146847d26bb5
153826e2cb98
hex1fb95fac9b

136254041243 has 8 divisors (see below), whose sum is σ = 140698654080. Its totient is φ = 131812511040.

The previous prime is 136254041179. The next prime is 136254041257. The reversal of 136254041243 is 342140452631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 136254041243 - 26 = 136254041179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136254041743) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 680648 + ... + 857781.

It is an arithmetic number, because the mean of its divisors is an integer number (17587331760).

Almost surely, 2136254041243 is an apocalyptic number.

136254041243 is a deficient number, since it is larger than the sum of its proper divisors (4444612837).

136254041243 is a wasteful number, since it uses less digits than its factorization.

136254041243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1541317.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 136254041243 its reverse (342140452631), we get a palindrome (478394493874).

The spelling of 136254041243 in words is "one hundred thirty-six billion, two hundred fifty-four million, forty-one thousand, two hundred forty-three".

Divisors: 1 31 2857 88567 1538429 47691299 4395291653 136254041243