Base | Representation |
---|---|
bin | 1100011001001010110110… |
… | …1101011100011000111011 |
3 | 1210020200111202001112121010 |
4 | 3012102231231130120323 |
5 | 3241224133430242133 |
6 | 44551541223045003 |
7 | 2604325425203634 |
oct | 306225555343073 |
9 | 53220452045533 |
10 | 13626550634043 |
11 | 4383a95653656 |
12 | 1640b002a0763 |
13 | 77ac9418c269 |
14 | 35175857688b |
15 | 1896d03c4263 |
hex | c64adb5c63b |
13626550634043 has 16 divisors (see below), whose sum is σ = 18283282085376. Its totient is φ = 9027271839840.
The previous prime is 13626550634023. The next prime is 13626550634131. The reversal of 13626550634043 is 34043605562631.
It is not a de Polignac number, because 13626550634043 - 237 = 13489111680571 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13626550633983 and 13626550634001.
It is not an unprimeable number, because it can be changed into a prime (13626550634023) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22032643 + ... + 22642668.
It is an arithmetic number, because the mean of its divisors is an integer number (1142705130336).
Almost surely, 213626550634043 is an apocalyptic number.
13626550634043 is a deficient number, since it is larger than the sum of its proper divisors (4656731451333).
13626550634043 is a wasteful number, since it uses less digits than its factorization.
13626550634043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44675954.
The product of its (nonzero) digits is 4665600, while the sum is 48.
The spelling of 13626550634043 in words is "thirteen trillion, six hundred twenty-six billion, five hundred fifty million, six hundred thirty-four thousand, forty-three".
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