1363240243345 has 8 divisors (see below), whose sum is σ = 1654269059880. Its totient is φ = 1078338349440.

The previous prime is 1363240243331. The next prime is 1363240243349. The reversal of 1363240243345 is 5433420423631.

It can be written as a sum of positive squares in 4 ways, for example, as 153172042384 + 1210068200961 = 391372^2 + 1100031^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1363240243345 - 2⁷ = 1363240243217 is a prime.

It is a super-2 number, since 2×1363240243345² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1363240243298 and 1363240243307.

It is not an unprimeable number, because it can be changed into a prime (1363240243349) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1531730166 + ... + 1531731055.

It is an arithmetic number, because the mean of its divisors is an integer number (206783632485).

Almost surely, 2^{1363240243345} is an apocalyptic number.

It is an amenable number.

1363240243345 is a deficient number, since it is larger than the sum of its proper divisors (291028816535).

1363240243345 is an equidigital number, since it uses as much as digits as its factorization.

1363240243345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3063461315.

The product of its (nonzero) digits is 622080, while the sum is 40.

Adding to 1363240243345 its reverse (5433420423631), we get a palindrome (6796660666976).

The spelling of 1363240243345 in words is "one trillion, three hundred sixty-three billion, two hundred forty million, two hundred forty-three thousand, three hundred forty-five".