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136326245201 = 251543132451
BaseRepresentation
bin111111011110110101…
…1010110101101010001
3111000212210212210120122
41332331223112231101
54213144004321301
6142343304320025
712564201651626
oct1767553265521
9430783783518
10136326245201
11528a767a853
1222507473015
13cb1772a2a3
14685376034d
15382d44181b
hex1fbdad6b51

136326245201 has 4 divisors (see below), whose sum is σ = 136869377904. Its totient is φ = 135783112500.

The previous prime is 136326245189. The next prime is 136326245233. The reversal of 136326245201 is 102542623631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136326245201 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (136326245281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271565975 + ... + 271566476.

It is an arithmetic number, because the mean of its divisors is an integer number (34217344476).

Almost surely, 2136326245201 is an apocalyptic number.

It is an amenable number.

136326245201 is a deficient number, since it is larger than the sum of its proper divisors (543132703).

136326245201 is an equidigital number, since it uses as much as digits as its factorization.

136326245201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 543132702.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 136326245201 its reverse (102542623631), we get a palindrome (238868868832).

The spelling of 136326245201 in words is "one hundred thirty-six billion, three hundred twenty-six million, two hundred forty-five thousand, two hundred one".

Divisors: 1 251 543132451 136326245201