1364134624051 has 4 divisors (see below), whose sum is σ = 1364473375192. Its totient is φ = 1363795872912.

The previous prime is 1364134624033. The next prime is 1364134624057. The reversal of 1364134624051 is 1504264314631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1364134624051 - 2⁷ = 1364134623923 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1364134623995 and 1364134624013.

It is not an unprimeable number, because it can be changed into a prime (1364134624057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169369530 + ... + 169377583.

It is an arithmetic number, because the mean of its divisors is an integer number (341118343798).

Almost surely, 2^{1364134624051} is an apocalyptic number.

1364134624051 is a deficient number, since it is larger than the sum of its proper divisors (338751141).

1364134624051 is an equidigital number, since it uses as much as digits as its factorization.

1364134624051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 338751140.

The product of its (nonzero) digits is 207360, while the sum is 40.

Adding to 1364134624051 its reverse (1504264314631), we get a palindrome (2868398938682).

The spelling of 1364134624051 in words is "one trillion, three hundred sixty-four billion, one hundred thirty-four million, six hundred twenty-four thousand, fifty-one".