Base | Representation |
---|---|
bin | 11001011010001011… |
… | …10011101110100011 |
3 | 1022012200200212202112 |
4 | 30231011303232203 |
5 | 210414144233303 |
6 | 10133342305535 |
7 | 662021660105 |
oct | 145505635643 |
9 | 38180625675 |
10 | 13641399203 |
11 | 587023a143 |
12 | 27885882ab |
13 | 1395233c63 |
14 | 935a0b575 |
15 | 54c8eb0d8 |
hex | 32d173ba3 |
13641399203 has 4 divisors (see below), whose sum is σ = 13662290208. Its totient is φ = 13620508200.
The previous prime is 13641399197. The next prime is 13641399217. The reversal of 13641399203 is 30299314631.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30299314631 = 173 ⋅175140547.
It is a cyclic number.
It is not a de Polignac number, because 13641399203 - 212 = 13641395107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13641399253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10444523 + ... + 10445828.
It is an arithmetic number, because the mean of its divisors is an integer number (3415572552).
Almost surely, 213641399203 is an apocalyptic number.
13641399203 is a deficient number, since it is larger than the sum of its proper divisors (20891005).
13641399203 is an equidigital number, since it uses as much as digits as its factorization.
13641399203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20891004.
The product of its (nonzero) digits is 104976, while the sum is 41.
The spelling of 13641399203 in words is "thirteen billion, six hundred forty-one million, three hundred ninety-nine thousand, two hundred three".
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