1364143955201 has 4 divisors (see below), whose sum is σ = 1364156102400. Its totient is φ = 1364131808004.

The previous prime is 1364143955197. The next prime is 1364143955221. The reversal of 1364143955201 is 1025593414631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1364143955201 - 2² = 1364143955197 is a prime.

It is a super-2 number, since 2×1364143955201² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1364143955221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5903561 + ... + 6130278.

It is an arithmetic number, because the mean of its divisors is an integer number (341039025600).

Almost surely, 2^{1364143955201} is an apocalyptic number.

It is an amenable number.

1364143955201 is a deficient number, since it is larger than the sum of its proper divisors (12147199).

1364143955201 is a wasteful number, since it uses less digits than its factorization.

1364143955201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12147198.

The product of its (nonzero) digits is 388800, while the sum is 44.

The spelling of 1364143955201 in words is "one trillion, three hundred sixty-four billion, one hundred forty-three million, nine hundred fifty-five thousand, two hundred one".