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136427051035 = 5113989621833
BaseRepresentation
bin111111100001110101…
…1111001100000011011
3111001010211120021012001
41333003223321200123
54213400311113120
6142401305101431
712566534541322
oct1770353714033
9431124507161
10136427051035
1152949571760
1222535187877
13cb32593802
146862cc10b9
153837204e0a
hex1fc3af981b

136427051035 has 16 divisors (see below), whose sum is σ = 178640471520. Its totient is φ = 99194640640.

The previous prime is 136427051027. The next prime is 136427051039. The reversal of 136427051035 is 530150724631.

It is not a de Polignac number, because 136427051035 - 23 = 136427051027 is a prime.

It is a super-2 number, since 2×1364270510352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 136427050985 and 136427051003.

It is not an unprimeable number, because it can be changed into a prime (136427051039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91522 + ... + 530311.

It is an arithmetic number, because the mean of its divisors is an integer number (11165029470).

Almost surely, 2136427051035 is an apocalyptic number.

136427051035 is a deficient number, since it is larger than the sum of its proper divisors (42213420485).

136427051035 is a wasteful number, since it uses less digits than its factorization.

136427051035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 625838.

The product of its (nonzero) digits is 75600, while the sum is 37.

Adding to 136427051035 its reverse (530150724631), we get a palindrome (666577775666).

The spelling of 136427051035 in words is "one hundred thirty-six billion, four hundred twenty-seven million, fifty-one thousand, thirty-five".

Divisors: 1 5 11 55 3989 19945 43879 219395 621833 3109165 6840163 34200815 2480491837 12402459185 27285410207 136427051035