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136431113 = 7131499243
BaseRepresentation
bin10000010000111…
…00011000001001
3100111201102022012
420020130120021
5234411243423
621312105305
73244434230
oct1010343011
9314642265
10136431113
1170014795
1239835235
132235aa90
1414195b17
15be9e078
hex821c609

136431113 has 8 divisors (see below), whose sum is σ = 167915328. Its totient is φ = 107945424.

The previous prime is 136431089. The next prime is 136431133. The reversal of 136431113 is 311134631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 136431113 - 216 = 136365577 is a prime.

It is a super-2 number, since 2×1364311132 = 37226897188837538, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (136431133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 749531 + ... + 749712.

It is an arithmetic number, because the mean of its divisors is an integer number (20989416).

Almost surely, 2136431113 is an apocalyptic number.

136431113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

136431113 is a deficient number, since it is larger than the sum of its proper divisors (31484215).

136431113 is a wasteful number, since it uses less digits than its factorization.

136431113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1499263.

The product of its digits is 648, while the sum is 23.

The square root of 136431113 is about 11680.3729820584. The cubic root of 136431113 is about 514.7991336558.

Adding to 136431113 its reverse (311134631), we get a palindrome (447565744).

The spelling of 136431113 in words is "one hundred thirty-six million, four hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 7 13 91 1499243 10494701 19490159 136431113