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13645354433 = 97911393663
BaseRepresentation
bin11001011010101001…
…11001010111000001
31022012222010211022112
430231110321113001
5210421202320213
610134003145105
7662100412304
oct145524712701
938188124275
1013645354433
1158724a0827
122789975195
131395cba329
1493635ab3b
1554ce2cea8
hex32d5395c1

13645354433 has 4 divisors (see below), whose sum is σ = 13646757888. Its totient is φ = 13643950980.

The previous prime is 13645354409. The next prime is 13645354447. The reversal of 13645354433 is 33445354631.

13645354433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13645354433 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13645354483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 687041 + ... + 706622.

It is an arithmetic number, because the mean of its divisors is an integer number (3411689472).

Almost surely, 213645354433 is an apocalyptic number.

It is an amenable number.

13645354433 is a deficient number, since it is larger than the sum of its proper divisors (1403455).

13645354433 is an equidigital number, since it uses as much as digits as its factorization.

13645354433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1403454.

The product of its digits is 777600, while the sum is 41.

The spelling of 13645354433 in words is "thirteen billion, six hundred forty-five million, three hundred fifty-four thousand, four hundred thirty-three".

Divisors: 1 9791 1393663 13645354433