Base | Representation |
---|---|
bin | 11001011011000000… |
… | …01110001100010001 |
3 | 1022020011201122220020 |
4 | 30231200032030101 |
5 | 210422432321340 |
6 | 10134150534053 |
7 | 662134556106 |
oct | 145540161421 |
9 | 38204648806 |
10 | 13648323345 |
11 | 5874139378 |
12 | 278a967329 |
13 | 13967b9797 |
14 | 9368d0aad |
15 | 54d3179d0 |
hex | 32d80e311 |
13648323345 has 16 divisors (see below), whose sum is σ = 22541747712. Its totient is φ = 7044295680.
The previous prime is 13648323343. The next prime is 13648323391. The reversal of 13648323345 is 54332384631.
It is not a de Polignac number, because 13648323345 - 21 = 13648323343 is a prime.
It is a super-3 number, since 3×136483233453 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13648323297 and 13648323306.
It is not an unprimeable number, because it can be changed into a prime (13648323343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14675152 + ... + 14676081.
It is an arithmetic number, because the mean of its divisors is an integer number (1408859232).
Almost surely, 213648323345 is an apocalyptic number.
13648323345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13648323345 is a deficient number, since it is larger than the sum of its proper divisors (8893424367).
13648323345 is a wasteful number, since it uses less digits than its factorization.
13648323345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29351272.
The product of its digits is 622080, while the sum is 42.
The spelling of 13648323345 in words is "thirteen billion, six hundred forty-eight million, three hundred twenty-three thousand, three hundred forty-five".
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