13650403531 has 4 divisors (see below), whose sum is σ = 13650738192. Its totient is φ = 13650068872.

The previous prime is 13650403523. The next prime is 13650403537. The reversal of 13650403531 is 13530405631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13650403531 - 2³ = 13650403523 is a prime.

It is a super-2 number, since 2×13650403531² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13650403493 and 13650403502.

It is not an unprimeable number, because it can be changed into a prime (13650403537) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96016 + ... + 191101.

It is an arithmetic number, because the mean of its divisors is an integer number (3412684548).

Almost surely, 2^13650403531 is an apocalyptic number.

13650403531 is a deficient number, since it is larger than the sum of its proper divisors (334661).

13650403531 is an equidigital number, since it uses as much as digits as its factorization.

13650403531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334660.

The product of its (nonzero) digits is 16200, while the sum is 31.

The spelling of 13650403531 in words is "thirteen billion, six hundred fifty million, four hundred three thousand, five hundred thirty-one".