Base | Representation |
---|---|
bin | 11111000010011001101001… |
… | …001100101111101100011011 |
3 | 122220022200202102101202010011 |
4 | 133002121221030233230123 |
5 | 120342442020340101420 |
6 | 1202153132432502351 |
7 | 40516055445514525 |
oct | 3702315114575433 |
9 | 586280672352104 |
10 | 136504415550235 |
11 | 3a549219a08347 |
12 | 133875786aa9b7 |
13 | 5b224077ab965 |
14 | 259cbc57b6a15 |
15 | 10babd6b2095a |
hex | 7c266932fb1b |
136504415550235 has 16 divisors (see below), whose sum is σ = 173454062294016. Its totient is φ = 102771998005248.
The previous prime is 136504415550227. The next prime is 136504415550259. The reversal of 136504415550235 is 532055514405631.
It is a cyclic number.
It is not a de Polignac number, because 136504415550235 - 23 = 136504415550227 is a prime.
It is a super-2 number, since 2×1365044155502352 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 59788734 + ... + 62029843.
It is an arithmetic number, because the mean of its divisors is an integer number (10840878893376).
Almost surely, 2136504415550235 is an apocalyptic number.
136504415550235 is a deficient number, since it is larger than the sum of its proper divisors (36949646743781).
136504415550235 is a wasteful number, since it uses less digits than its factorization.
136504415550235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121831782.
The product of its (nonzero) digits is 5400000, while the sum is 49.
Adding to 136504415550235 its reverse (532055514405631), we get a palindrome (668559929955866).
The spelling of 136504415550235 in words is "one hundred thirty-six trillion, five hundred four billion, four hundred fifteen million, five hundred fifty thousand, two hundred thirty-five".
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