13651245641001 has 4 divisors (see below), whose sum is σ = 18201660854672. Its totient is φ = 9100830427332.

The previous prime is 13651245640999. The next prime is 13651245641081. The reversal of 13651245641001 is 10014654215631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13651245641001 - 2¹ = 13651245640999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13651245641081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2275207606831 + ... + 2275207606836.

It is an arithmetic number, because the mean of its divisors is an integer number (4550415213668).

Almost surely, 2^{13651245641001} is an apocalyptic number.

It is an amenable number.

13651245641001 is a deficient number, since it is larger than the sum of its proper divisors (4550415213671).

13651245641001 is an equidigital number, since it uses as much as digits as its factorization.

13651245641001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4550415213670.

The product of its (nonzero) digits is 86400, while the sum is 39.

Adding to 13651245641001 its reverse (10014654215631), we get a palindrome (23665899856632).

The spelling of 13651245641001 in words is "thirteen trillion, six hundred fifty-one billion, two hundred forty-five million, six hundred forty-one thousand, one".