Base | Representation |
---|---|
bin | 111111100101100011… |
… | …0011011011011011001 |
3 | 111001110111122012022121 |
4 | 1333023012123123121 |
5 | 4214124132234413 |
6 | 142421511221241 |
7 | 12602605066456 |
oct | 1771306333331 |
9 | 431414565277 |
10 | 136551446233 |
11 | 52a02805704 |
12 | 2256a977821 |
13 | cb52299137 |
14 | 687562282d |
15 | 38430c7b8d |
hex | 1fcb19b6d9 |
136551446233 has 4 divisors (see below), whose sum is σ = 136559530240. Its totient is φ = 136543362228.
The previous prime is 136551446219. The next prime is 136551446263. The reversal of 136551446233 is 332644155631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 136551446233 - 29 = 136551445721 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 136551446233.
It is not an unprimeable number, because it can be changed into a prime (136551446203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4016613 + ... + 4050466.
It is an arithmetic number, because the mean of its divisors is an integer number (34139882560).
Almost surely, 2136551446233 is an apocalyptic number.
It is an amenable number.
136551446233 is a deficient number, since it is larger than the sum of its proper divisors (8084007).
136551446233 is an equidigital number, since it uses as much as digits as its factorization.
136551446233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8084006.
The product of its digits is 777600, while the sum is 43.
The spelling of 136551446233 in words is "one hundred thirty-six billion, five hundred fifty-one million, four hundred forty-six thousand, two hundred thirty-three".
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