136554413057 has 4 divisors (see below), whose sum is σ = 137155974576. Its totient is φ = 135952851540.

The previous prime is 136554413053. The next prime is 136554413069. The reversal of 136554413057 is 750314455631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 136554413057 - 2² = 136554413053 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136554412999 and 136554413017.

It is not an unprimeable number, because it can be changed into a prime (136554413053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 300780419 + ... + 300780872.

It is an arithmetic number, because the mean of its divisors is an integer number (34288993644).

Almost surely, 2^136554413057 is an apocalyptic number.

It is an amenable number.

136554413057 is a deficient number, since it is larger than the sum of its proper divisors (601561519).

136554413057 is an equidigital number, since it uses as much as digits as its factorization.

136554413057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 601561518.

The product of its (nonzero) digits is 756000, while the sum is 44.

Adding to 136554413057 its reverse (750314455631), we get a palindrome (886868868688).

The spelling of 136554413057 in words is "one hundred thirty-six billion, five hundred fifty-four million, four hundred thirteen thousand, fifty-seven".