Base | Representation |
---|---|
bin | 11111000101100101111001… |
… | …011001000010011110110011 |
3 | 122221002122211212020121010011 |
4 | 133011211321121002132303 |
5 | 120410040200004243332 |
6 | 1202442003102115351 |
7 | 40540651333256440 |
oct | 3705457131023663 |
9 | 587078755217104 |
10 | 136723730540467 |
11 | 3a623232567594 |
12 | 13401b8487bb57 |
13 | 5b39cb95b4425 |
14 | 25a966cbc89c7 |
15 | 10c1770aeee47 |
hex | 7c59796427b3 |
136723730540467 has 4 divisors (see below), whose sum is σ = 156255692046256. Its totient is φ = 117191769034680.
The previous prime is 136723730540447. The next prime is 136723730540489. The reversal of 136723730540467 is 764045037327631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136723730540467 - 231 = 136721583056819 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (136723730540407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9765980752884 + ... + 9765980752897.
It is an arithmetic number, because the mean of its divisors is an integer number (39063923011564).
Almost surely, 2136723730540467 is an apocalyptic number.
136723730540467 is a deficient number, since it is larger than the sum of its proper divisors (19531961505789).
136723730540467 is an equidigital number, since it uses as much as digits as its factorization.
136723730540467 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19531961505788.
The product of its (nonzero) digits is 53343360, while the sum is 58.
The spelling of 136723730540467 in words is "one hundred thirty-six trillion, seven hundred twenty-three billion, seven hundred thirty million, five hundred forty thousand, four hundred sixty-seven".
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