13674043063913 has 4 divisors (see below), whose sum is σ = 13678177945680. Its totient is φ = 13669908182148.

The previous prime is 13674043063883. The next prime is 13674043063937. The reversal of 13674043063913 is 31936034047631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13674043063913 is a prime.

It is a super-4 number, since 4×13674043063913⁴ (a number of 54 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13674043065913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2067435923 + ... + 2067442536.

It is an arithmetic number, because the mean of its divisors is an integer number (3419544486420).

Almost surely, 2^{13674043063913} is an apocalyptic number.

It is an amenable number.

13674043063913 is a deficient number, since it is larger than the sum of its proper divisors (4134881767).

13674043063913 is an equidigital number, since it uses as much as digits as its factorization.

13674043063913 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4134881766.

The product of its (nonzero) digits is 2939328, while the sum is 50.

The spelling of 13674043063913 in words is "thirteen trillion, six hundred seventy-four billion, forty-three million, sixty-three thousand, nine hundred thirteen".