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13680614833 = 17804742049
BaseRepresentation
bin11001011110110110…
…11001110110110001
31022022102111020111021
430233123121312301
5211004214133313
610141303015441
7663006210304
oct145733316661
938272436437
1013680614833
115890394456
12279973a581
1313a03b4782
1493acd8b3b
1555109578d
hex32f6d9db1

13680614833 has 4 divisors (see below), whose sum is σ = 14485356900. Its totient is φ = 12875872768.

The previous prime is 13680614813. The next prime is 13680614869. The reversal of 13680614833 is 33841608631.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33841608631 = 101773325303.

It can be written as a sum of positive squares in 2 ways, for example, as 11250420624 + 2430194209 = 106068^2 + 49297^2 .

It is a cyclic number.

It is not a de Polignac number, because 13680614833 - 221 = 13678517681 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13680614833.

It is not an unprimeable number, because it can be changed into a prime (13680614803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402371008 + ... + 402371041.

It is an arithmetic number, because the mean of its divisors is an integer number (3621339225).

Almost surely, 213680614833 is an apocalyptic number.

It is an amenable number.

13680614833 is a deficient number, since it is larger than the sum of its proper divisors (804742067).

13680614833 is an equidigital number, since it uses as much as digits as its factorization.

13680614833 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 804742066.

The product of its (nonzero) digits is 248832, while the sum is 43.

The spelling of 13680614833 in words is "thirteen billion, six hundred eighty million, six hundred fourteen thousand, eight hundred thirty-three".

Divisors: 1 17 804742049 13680614833