Base | Representation |
---|---|
bin | 111111101101101110… |
… | …1001101100001000001 |
3 | 111002011121222120000212 |
4 | 1333123131031201001 |
5 | 4220204404312032 |
6 | 142505032523505 |
7 | 12612446366246 |
oct | 1773335154101 |
9 | 432147876025 |
10 | 136825854017 |
11 | 5303369a2a6 |
12 | 22626850595 |
13 | cb970a62c8 |
14 | 689dc535cd |
15 | 385c22dbb2 |
hex | 1fdb74d841 |
136825854017 has 4 divisors (see below), whose sum is σ = 136921604820. Its totient is φ = 136730103216.
The previous prime is 136825853987. The next prime is 136825854019. The reversal of 136825854017 is 710458528631.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 28380119296 + 108445734721 = 168464^2 + 329311^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136825854017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (136825854019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47873258 + ... + 47876115.
It is an arithmetic number, because the mean of its divisors is an integer number (34230401205).
Almost surely, 2136825854017 is an apocalyptic number.
It is an amenable number.
136825854017 is a deficient number, since it is larger than the sum of its proper divisors (95750803).
136825854017 is an equidigital number, since it uses as much as digits as its factorization.
136825854017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95750802.
The product of its (nonzero) digits is 1612800, while the sum is 50.
The spelling of 136825854017 in words is "one hundred thirty-six billion, eight hundred twenty-five million, eight hundred fifty-four thousand, seventeen".
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