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13687322323657 = 46329562251239
BaseRepresentation
bin1100011100101101001111…
…1111000010101011001001
31210110111101000201020111011
43013023103333002223021
53243223114003324112
645035511415203521
72611606415064403
oct307132377025311
953414330636434
1013687322323657
1143a7840695524
1216508406765a1
1378392a769408
14354681705b73
1518b08a75aaa7
hexc72d3fc2ac9

13687322323657 has 4 divisors (see below), whose sum is σ = 13716884575360. Its totient is φ = 13657760071956.

The previous prime is 13687322323613. The next prime is 13687322323687. The reversal of 13687322323657 is 75632322378631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13687322323657 is a prime.

It is a super-4 number, since 4×136873223236574 (a number of 54 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13687322323687) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14781125157 + ... + 14781126082.

It is an arithmetic number, because the mean of its divisors is an integer number (3429221143840).

Almost surely, 213687322323657 is an apocalyptic number.

It is an amenable number.

13687322323657 is a deficient number, since it is larger than the sum of its proper divisors (29562251703).

13687322323657 is an equidigital number, since it uses as much as digits as its factorization.

13687322323657 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29562251702.

The product of its digits is 45722880, while the sum is 58.

The spelling of 13687322323657 in words is "thirteen trillion, six hundred eighty-seven billion, three hundred twenty-two million, three hundred twenty-three thousand, six hundred fifty-seven".

Divisors: 1 463 29562251239 13687322323657