136940233 has 4 divisors (see below), whose sum is σ = 141662340. Its totient is φ = 132218128.

The previous prime is 136940227. The next prime is 136940257. The reversal of 136940233 is 332049631.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 332049631 = 239 ⋅1389329.

It can be written as a sum of positive squares in 2 ways, for example, as 113784889 + 23155344 = 10667^2 + 4812^2 .

It is a cyclic number.

It is not a de Polignac number, because 136940233 - 2¹⁷ = 136809161 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136940195 and 136940204.

It is not an unprimeable number, because it can be changed into a prime (136940203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2361010 + ... + 2361067.

It is an arithmetic number, because the mean of its divisors is an integer number (35415585).

Almost surely, 2^136940233 is an apocalyptic number.

It is an amenable number.

136940233 is a deficient number, since it is larger than the sum of its proper divisors (4722107).

136940233 is an equidigital number, since it uses as much as digits as its factorization.

136940233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4722106.

The product of its (nonzero) digits is 11664, while the sum is 31.

The square root of 136940233 is about 11702.1465124993. The cubic root of 136940233 is about 515.4386974229.

Adding to 136940233 its reverse (332049631), we get a palindrome (468989864).

The spelling of 136940233 in words is "one hundred thirty-six million, nine hundred forty thousand, two hundred thirty-three".