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137066566457003 = 666120577475823
BaseRepresentation
bin11111001010100101001100…
…000000010001011010101011
3122222022102202200111122111112
4133022211030000101122223
5120431144312003111003
61203303302241420535
740604506202421131
oct3712451400213253
9588272680448445
10137066566457003
113a7456714a09a7
121345850393a74b
135b63424b897c1
1425bc0b2dcb751
1510ca638c273d8
hex7ca94c0116ab

137066566457003 has 4 divisors (see below), whose sum is σ = 137087143939488. Its totient is φ = 137045988974520.

The previous prime is 137066566456979. The next prime is 137066566457039. The reversal of 137066566457003 is 300754665660731.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 137066566457003 - 214 = 137066566440619 is a prime.

It is a super-3 number, since 3×1370665664570033 (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (137066566457503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10288731251 + ... + 10288744572.

It is an arithmetic number, because the mean of its divisors is an integer number (34271785984872).

Almost surely, 2137066566457003 is an apocalyptic number.

137066566457003 is a deficient number, since it is larger than the sum of its proper divisors (20577482485).

137066566457003 is an equidigital number, since it uses as much as digits as its factorization.

137066566457003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20577482484.

The product of its (nonzero) digits is 57153600, while the sum is 59.

The spelling of 137066566457003 in words is "one hundred thirty-seven trillion, sixty-six billion, five hundred sixty-six million, four hundred fifty-seven thousand, three".

Divisors: 1 6661 20577475823 137066566457003