Base | Representation |
---|---|
bin | 111111110110001101… |
… | …0011010111010100011 |
3 | 111002220110021200202201 |
4 | 1333230122122322203 |
5 | 4221300221211024 |
6 | 142553154154031 |
7 | 12622502422261 |
oct | 1775432327243 |
9 | 432813250681 |
10 | 137110335139 |
11 | 5316a234168 |
12 | 226a5b82917 |
13 | cc10ccc52b |
14 | 68c9947431 |
15 | 38771c4744 |
hex | 1fec69aea3 |
137110335139 has 4 divisors (see below), whose sum is σ = 141838277760. Its totient is φ = 132382392520.
The previous prime is 137110335133. The next prime is 137110335163. The reversal of 137110335139 is 931533011731.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-137110335139 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 137110335098 and 137110335107.
It is not an unprimeable number, because it can be changed into a prime (137110335133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2363971267 + ... + 2363971324.
It is an arithmetic number, because the mean of its divisors is an integer number (35459569440).
Almost surely, 2137110335139 is an apocalyptic number.
137110335139 is a deficient number, since it is larger than the sum of its proper divisors (4727942621).
137110335139 is an equidigital number, since it uses as much as digits as its factorization.
137110335139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4727942620.
The product of its (nonzero) digits is 25515, while the sum is 37.
The spelling of 137110335139 in words is "one hundred thirty-seven billion, one hundred ten million, three hundred thirty-five thousand, one hundred thirty-nine".
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