Search a number
-
+
13712054640145 = 52742410928029
BaseRepresentation
bin1100011110001001011000…
…1001010101111000010001
31210112212012122221002112221
43013202112021111320101
53244124241441441040
645055121514421041
72613443332233361
oct307422611257021
953485178832487
1013712054640145
11440728240aa04
1216555a3431781
1378606c6ab304
1435594a2cc9a1
1518ba36ba474a
hexc7896255e11

13712054640145 has 4 divisors (see below), whose sum is σ = 16454465568180. Its totient is φ = 10969643712112.

The previous prime is 13712054640139. The next prime is 13712054640197. The reversal of 13712054640145 is 54104645021731.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7441978544001 + 6270076096144 = 2727999^2 + 2504012^2 .

It is a cyclic number.

It is not a de Polignac number, because 13712054640145 - 25 = 13712054640113 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1371205464010 + ... + 1371205464019.

It is an arithmetic number, because the mean of its divisors is an integer number (4113616392045).

Almost surely, 213712054640145 is an apocalyptic number.

It is an amenable number.

13712054640145 is a deficient number, since it is larger than the sum of its proper divisors (2742410928035).

13712054640145 is an equidigital number, since it uses as much as digits as its factorization.

13712054640145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2742410928034.

The product of its (nonzero) digits is 403200, while the sum is 43.

Adding to 13712054640145 its reverse (54104645021731), we get a palindrome (67816699661876).

The spelling of 13712054640145 in words is "thirteen trillion, seven hundred twelve billion, fifty-four million, six hundred forty thousand, one hundred forty-five".

Divisors: 1 5 2742410928029 13712054640145