Base | Representation |
---|---|
bin | 1100011110001001011000… |
… | …1001010101111000010001 |
3 | 1210112212012122221002112221 |
4 | 3013202112021111320101 |
5 | 3244124241441441040 |
6 | 45055121514421041 |
7 | 2613443332233361 |
oct | 307422611257021 |
9 | 53485178832487 |
10 | 13712054640145 |
11 | 440728240aa04 |
12 | 16555a3431781 |
13 | 78606c6ab304 |
14 | 35594a2cc9a1 |
15 | 18ba36ba474a |
hex | c7896255e11 |
13712054640145 has 4 divisors (see below), whose sum is σ = 16454465568180. Its totient is φ = 10969643712112.
The previous prime is 13712054640139. The next prime is 13712054640197. The reversal of 13712054640145 is 54104645021731.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7441978544001 + 6270076096144 = 2727999^2 + 2504012^2 .
It is a cyclic number.
It is not a de Polignac number, because 13712054640145 - 25 = 13712054640113 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1371205464010 + ... + 1371205464019.
It is an arithmetic number, because the mean of its divisors is an integer number (4113616392045).
Almost surely, 213712054640145 is an apocalyptic number.
It is an amenable number.
13712054640145 is a deficient number, since it is larger than the sum of its proper divisors (2742410928035).
13712054640145 is an equidigital number, since it uses as much as digits as its factorization.
13712054640145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2742410928034.
The product of its (nonzero) digits is 403200, while the sum is 43.
Adding to 13712054640145 its reverse (54104645021731), we get a palindrome (67816699661876).
The spelling of 13712054640145 in words is "thirteen trillion, seven hundred twelve billion, fifty-four million, six hundred forty thousand, one hundred forty-five".
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