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137224426081 = 148192656601
BaseRepresentation
bin111111111001100110…
…1101001001001100001
3111010012101222010010011
41333303031221021201
54222013423113311
6143012351404521
712625356243031
oct1776315511141
9433171863104
10137224426081
115321867a3a6
1222718223741
13cc2b837972
1468dab658c1
15388220e321
hex1ff3369261

137224426081 has 4 divisors (see below), whose sum is σ = 137317084164. Its totient is φ = 137131768000.

The previous prime is 137224426067. The next prime is 137224426091. The reversal of 137224426081 is 180624422731.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 79087500625 + 58136925456 = 281225^2 + 241116^2 .

It is a cyclic number.

It is not a de Polignac number, because 137224426081 - 25 = 137224426049 is a prime.

It is a super-2 number, since 2×1372244260812 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (137224426051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46326820 + ... + 46329781.

It is an arithmetic number, because the mean of its divisors is an integer number (34329271041).

Almost surely, 2137224426081 is an apocalyptic number.

It is an amenable number.

137224426081 is a deficient number, since it is larger than the sum of its proper divisors (92658083).

137224426081 is an equidigital number, since it uses as much as digits as its factorization.

137224426081 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92658082.

The product of its (nonzero) digits is 129024, while the sum is 40.

The spelling of 137224426081 in words is "one hundred thirty-seven billion, two hundred twenty-four million, four hundred twenty-six thousand, eighty-one".

Divisors: 1 1481 92656601 137224426081