Search a number
-
+
137250659193 = 345750219731
BaseRepresentation
bin111111111010011000…
…1101101101101111001
3111010021020022220011220
41333310301231231321
54222042132043233
6143015125542253
712626125232304
oct1776461555571
9433236286156
10137250659193
115323146775a
1222724b74989
13cc340c120b
146900433b3b
153884691eb3
hex1ff4c6db79

137250659193 has 4 divisors (see below), whose sum is σ = 183000878928. Its totient is φ = 91500439460.

The previous prime is 137250659171. The next prime is 137250659201. The reversal of 137250659193 is 391956052731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 137250659193 - 26 = 137250659129 is a prime.

It is a super-2 number, since 2×1372506591932 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (137250659393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22875109863 + ... + 22875109868.

It is an arithmetic number, because the mean of its divisors is an integer number (45750219732).

Almost surely, 2137250659193 is an apocalyptic number.

It is an amenable number.

137250659193 is a deficient number, since it is larger than the sum of its proper divisors (45750219735).

137250659193 is an equidigital number, since it uses as much as digits as its factorization.

137250659193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45750219734.

The product of its (nonzero) digits is 1530900, while the sum is 51.

The spelling of 137250659193 in words is "one hundred thirty-seven billion, two hundred fifty million, six hundred fifty-nine thousand, one hundred ninety-three".

Divisors: 1 3 45750219731 137250659193