13740440131 has 8 divisors (see below), whose sum is σ = 15090174000. Its totient is φ = 12407473440.

The previous prime is 13740440123. The next prime is 13740440141. The reversal of 13740440131 is 13104404731.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13740440131 - 2³ = 13740440123 is a prime.

It is a super-2 number, since 2×13740440131² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13740440131.

It is not an unprimeable number, because it can be changed into a prime (13740440141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4190076 + ... + 4193353.

It is an arithmetic number, because the mean of its divisors is an integer number (1886271750).

Almost surely, 2^13740440131 is an apocalyptic number.

13740440131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13740440131 is a deficient number, since it is larger than the sum of its proper divisors (1349733869).

13740440131 is a wasteful number, since it uses less digits than its factorization.

13740440131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8383589.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 13740440131 its reverse (13104404731), we get a palindrome (26844844862).

The spelling of 13740440131 in words is "thirteen billion, seven hundred forty million, four hundred forty thousand, one hundred thirty-one".