Base | Representation |
---|---|
bin | 11001100110100101… |
… | …10100000111010001 |
3 | 1022110221112022201211 |
4 | 30303102310013101 |
5 | 211122320100303 |
6 | 10151541100121 |
7 | 664424404153 |
oct | 146322640721 |
9 | 38427468654 |
10 | 13745471953 |
11 | 5913a62584 |
12 | 27b73b7641 |
13 | 13b0972475 |
14 | 94577cad3 |
15 | 556b0766d |
hex | 3334b41d1 |
13745471953 has 4 divisors (see below), whose sum is σ = 13745755828. Its totient is φ = 13745188080.
The previous prime is 13745471947. The next prime is 13745471969. The reversal of 13745471953 is 35917454731.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11214174609 + 2531297344 = 105897^2 + 50312^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13745471953 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13745471897 and 13745471906.
It is not an unprimeable number, because it can be changed into a prime (13745471153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49038 + ... + 172903.
It is an arithmetic number, because the mean of its divisors is an integer number (3436438957).
Almost surely, 213745471953 is an apocalyptic number.
It is an amenable number.
13745471953 is a deficient number, since it is larger than the sum of its proper divisors (283875).
13745471953 is an equidigital number, since it uses as much as digits as its factorization.
13745471953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283874.
The product of its digits is 1587600, while the sum is 49.
The spelling of 13745471953 in words is "thirteen billion, seven hundred forty-five million, four hundred seventy-one thousand, nine hundred fifty-three".
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